bluh bluh

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@@ -2221,7 +2221,41 @@ We prove that symmetric simulation is a bisimulation for the case that $FX=X+1$.
Assuming $\alpha(x_1)=\bot\;\&\; \alpha(x_2)=\bot$ we have $(p_i+1)\comp\beta(x_1,x_2)=\bot=\alpha(x_i)$, and assuming $\alpha(x_1)\in X\;\&\;\alpha(x_2)\in X$ we have $(p_i+1)\comp\beta(x_1,x_2)=\alpha(x_i)\in X$.\qed
\end{proof}
Now, we give another proof for this functor. This proof is similar to the proof that we have given for the powerset functor.
\begin{lemma}
The order structure on the set-functor $FX=X+1$ is a liftable order.
\end{lemma}
\begin{proof}
By~\autoref{lem:set-ord-str}, assuming $h\in\Hom(1,Y+1)$, $k\in\Hom(1,X+1)$, $g\c X\to Y$, and $h\appr (g+1)(k)$, we need to prove that exists $k'\in\Hom(1,X+1)$ such that $(g+1)(k')=h$. Since $h\in\Hom(1,Y+1)$ we have two cases:
\begin{itemize}
\item $h=\bot$: In this case we take $k'=\bot$, then we have $g+1(k')=\bot=h$.
\item $g+1(k)=h$: In this case we take $k'=k$, then we have $g+1(k')=h$, and they are both an element of $Y$.\qed
\end{itemize}
\end{proof}
So, proven by Dubut, for every symmetric AM-simulation relation over a coalgebra $(X,\alpha)$ of the maybe functor, we have a witness $\sigma\c R\to R+1$ such that $\alpha\comp p_1=(p_1+1)\comp\sigma$.
\begin{prop}\label{prop:sym-rel-bisim-may}
Assuming that $R$ is a symmetric relation, and $\sigma\c R\to R+1$ is a witness for $R$ to be a simulation, for which $(p_1+1)\comp\sigma=\alpha\comp p_1$, then the following morphism is a witness for $R$ to be a bisimulation:
\begin{gather*}
\sigma\join((s+1)\comp\sigma\comp s)
\end{gather*}
\end{prop}
\begin{proof}
For every $(x_1,x_2)\in R$ by~\autoref{lem:proj-dist-set} and~\autoref{lem:sim-opsim-inc}.\ref{item:sim-opsim-inc:I} we have
\begin{gather*}
\powf p_1\comp(\sigma\join(\powf s\comp\sigma\comp s))(x_1,x_2)=
\powf p_1\comp\sigma(x_1,x_2).
\end{gather*}
% and by~\autoref{lem:alph-prod},
Recall that $\powf p_1\comp\sigma(x_1,x_2)=\alpha(x_1)$. By~\autoref{lem:proj-dist-set} and~\autoref{lem:sim-opsim-inc}.\ref{item:sim-opsim-inc:II} we have
\begin{gather*}
\powf p_2\comp(\sigma\join(\powf s\comp\sigma\comp s))(x_1,x_2)=
\powf p_2\comp(\powf s\comp\sigma\comp s)(x_1,x_2).
\end{gather*}
Since $\powf p_1\comp\sigma=\alpha\comp p_1$ by precomposing $s$ to the both sides of the equation we get $\powf p_2\comp(\powf s\comp\sigma\comp s)=\alpha\comp p_2$. So, $\sigma\join(\powf s\comp\sigma\comp s)$ is a witness for $R$ to be an AM bisimulation.\qed
\end{proof}
\section{Relators}
\subsection{Two-way similarity in Hughes-Jacobs}