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944bd831b6
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| 944bd831b6 | |||
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@@ -2171,7 +2171,24 @@ We take $R=\{(1,1),(1,2),(2,1),(2,2)\}$, and $X=\{1,2,3\}$. $\alpha$ is defined
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\{1,2\} & x=1 \\
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\{2,3\} & x=2\\
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\{3\} & x=3
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\end{cases}
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\end{cases}\qquad
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\begin{tikzpicture}[scale=0.1]
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\tikzstyle{every node}+=[inner sep=0pt]
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\draw [black] (23.8,-25.2) circle (3);
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\draw (23.8,-25.2) node {$1$};
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\draw [black] (42.4,-25.2) circle (3);
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\draw (42.4,-25.2) node {$2$};
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\draw [black] (33,-34.6) circle (3);
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\draw (33,-34.6) node {$3$};
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\draw [black] (22.477,-22.52) arc (234:-54:2.25);
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\fill [black] (25.12,-22.52) -- (26,-22.17) -- (25.19,-21.58);
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\draw [black] (41.077,-22.52) arc (234:-54:2.25);
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\fill [black] (43.72,-22.52) -- (44.6,-22.17) -- (43.79,-21.58);
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\draw [black] (26.8,-25.2) -- (39.4,-25.2);
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\fill [black] (39.4,-25.2) -- (38.6,-24.7) -- (38.6,-25.7);
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\draw [black] (40.28,-27.32) -- (35.12,-32.48);
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\fill [black] (35.12,-32.48) -- (36.04,-32.27) -- (35.33,-31.56);
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\end{tikzpicture}
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\end{gather*}
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$\sigma$ is defined as below:
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\begin{gather*}
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@@ -3137,6 +3154,15 @@ Barr relator is a generalization of the Egli-Milner relator, where the functor i
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\begin{proof}
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They all follow in an obvious way from~\autoref{lem:liftable} and~\autoref{lem:coliftable}. The last one needs $\appr\comp\appr=\appr$ that comes from transitivity of $\appr$. \qed
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\end{proof}
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\begin{prop}\label{prop:lax-relator-full-comm}
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Assuming the axiom of choice, for a functor $F$ with a liftable order we have:
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\begin{gather*}
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\bar{F}r\comp\appr=\appr\comp\bar{F}
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\end{gather*}
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\end{prop}
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\begin{proof}
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\todo{Write it down. You have it in your notes.}
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\end{proof}
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%\begin{example}
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% In the category of sets, subset over the powerset functor is an example of a liftable order. Using~\autoref{lem:set-ord-str} we only prove the case for every $h\in\Hom(1,\powf Z)$, $k\in\Hom(1,\powf Y)$. Additionally, for every $g\c Y\to Z$, such that $h\subseteq\powf g(k)$, we define $k'\in\powf Y$ that that $k'=\{y\mid g(y)\in h\}$. We show that $\powf g(k')=h$.
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%
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@@ -3258,7 +3284,22 @@ Perhaps if we can relax the definition of liftable by allowing $g$ to be a relat
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\begin{remark}
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With a similar argument we can prove that the symmetrization of a right-lax Barr-relator of $F$ is a Barr-relator.
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\end{remark}
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\todo{Try $FX=\powf(X^2)$ to see if the symmetrization of its lax Barr relator is a Barr relator. The order is just the set inclusion.}
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\begin{lemma}\label{lem:lax-relator-str}
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For a relation $r$, for functions $k_s\c F\pi_1(\bar{F}r)\to\powf FX$ and $k_b\c F\pi_2(\bar{F}r)\to\powf FX$, defined as
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\begin{gather*}
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k_s(x)=\{(x',y)\mid(x,y)\in\bar{F}r,x'\appr x, (x',y)\notin\bar{F}r\},\\
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k_b(x)=\{(x',y)\mid(x,y)\in\bar{F}r,x\appr x', (x',y)\notin\bar{F}r\},
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\end{gather*}
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we have
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\begin{gather*}
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(\bar{F}r)\comp\appr=\bar{F}r\cup(\bigcup_{x\in F\pi_1(\bar{F}r)} k_s(x)),\\
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(\bar{F}r)\comp\sappr=\bar{F}r\cup(\bigcup_{x\in F\pi_1(\bar{F}r)} k_b(x)).
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\end{gather*}
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\end{lemma}
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\begin{proof}
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\todo{Write it down. You have it in your notes.}
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\end{proof}
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\todo{Try $FX=\powf(X^2)$ to see if the symmetrization of its lax Barr relator is a Barr relator. The order is just the set inclusion. See if~\autoref{prop:lax-relator-full-comm} or~\autoref{lem:lax-relator-str} can help!}
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\end{document}
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