a proof
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@ -2194,13 +2194,28 @@ For every relation $r\rto X\to Y$ $\emre r=\subseteq\;\emre r=\emre r\;\subseteq
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Barr relator is a generalization of the Egli-Milner relator, where the functor is generalized.
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\begin{definition}
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\begin{definition}[Barr relator]
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A relator over a functor $F$ is a Barr relator, shown by $\bar{F}$, iff for a relation $r\c X\rto Y$, and a span $(\pi_1\c A\to X,\pi_2\c A\to Y)$ that $r=\pi_2\comp\pi_1^\op$ we have:
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\begin{gather*}
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\bar{F}r=F\pi_2\comp(F\pi_1)^\op
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\end{gather*}
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\end{definition}
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\begin{prop}
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For every set-functor $F$, the barr relator $\bar{F}$ is symmetric.
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\end{prop}
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\begin{proof}
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Assuming that for a span $(\pi_1\c A\to X,\pi_2\c A\to Y)$ we have $r=\pi_2\comp\pi_1^\op$, then we have:
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\begin{align*}
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\hat{\bar{F}}r&\\
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=&\bar{F}r\cap(\bar{F}r^\op)^\op\\
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=&\bar{F}(\pi_2\comp\pi_1^\op)\cap(\bar{F}(\pi_2\comp\pi_1^\op)^\op)^\op\\
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=&\bar{F}(\pi_2\comp\pi_1^\op)\cap(\bar{F}(\pi_1\comp\pi_2^\op))^\op\\
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=&F\pi_2\comp(F\pi_1)^\op\cap(F\pi_1\comp (F\pi_2)^\op)^\op\\
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=&F\pi_2\comp(F\pi_1)^\op\cap F\pi_2\comp (F\pi_1)^\op\\
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=&F\pi_2\comp(F\pi_1)^\op\\
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=&\bar{F}r
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\end{align*}
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\end{proof}
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\begin{prop}
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$\hat{L}$ is a Barr relator.
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\end{prop}
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